This exam named as CSIR NET is conducted by CSIR (Council of Scientific and Industrial Research) with the objective to determine the eligibility of the candidates of India, which is awarded with Junior Research Fellowships (JRF) /NET (National Eligibility Test) and also to determine eligibility for the appointment of Lecturers (NET) in a number of subjects that fall under the stream of Science & Technology. Exams conducted by CSIR are in the following areas:-
M.sc or equivalent degree/B.E./B.Tech/MBBS/B.Pharma/BS-4years/Integrated BS-MS with 55% marks for general and OBC-Non Creamy layer candidates and 50% of SC/ST, Persons with disability (PwD) candidates.
Candidates who enrolled for M.Sc or having completed 10+2+3 years of the above qualifying examination, candidates whose result are awaited (RA) are also eligible to apply to the condition that they complete their degree with the requisite percentage of marks within the validity period of two years to avail the fellowship from the effective date of the award.
These types of candidates will have to submit the attestation format (Given on reverse of the application form) duly certified by the Head of the Department/Institute from where the candidate appears or has appeared.
B. SC (Hons) or equivalent degree holders or students enrolled in Integrated MS-PhD program with at least 55 % marks for general and OBC (Non Creamy Layer) candidates; 50% marks for Sc/ST, persons with disability (PwD) are also eligible. The candidates who acquired only a bachelor’s degree will be eligible for the fellowship only after getting enrolled/registered for PhD/ Integrated PhD program within the validity period i.e. 2 years.
The eligibility for lectureship of NET qualified candidates depends on the subject to fulfilling the criteria laid down by UGC. PhD degree holders who have passed Master Degree with minimum 50% marks eligible to apply for Lectureship only.
The exam will be conducted in more than 27 cities which are spread all over the India. Name of the centres is defined below
Any candidate may opt any of the above describe centers. No request for the change of the center would be granted, however, request in writing may entertain on the merits. If at any center the numbers of appearing candidates are not sufficient, then that particular center may be deleted or any other nearest center will be allotted to the candidate at the discretion of CSIR. No TA/ DA will be allotted to any candidate for attending the exam in any manner.
|Exam Name||Age Limit|
|JRF (NET)||Maximum 28 years at the time of appearing in the exam (This limit may be relaxed up to 5 years in case of SC/ST/OBC(non Creamy Layer)/ Persons with Disability and female applicants)|
|LS (NET)||No Upper Age Limit|
There are three parts in the CSIR Question Paper named as (A, B & C) as per syllabus & Scheme of Exam
Part A: This is common to all subjects. This part contains questions related to General Aptitude with emphasis on logical reasoning, graphical analysis, numerical ability, quantitative comparison, puzzles, series formation and analytics etc.
Part B: This part contains Multiple Choice Questions (MCQs) covering all the topics in the syllabus
Part C: This is the trickiest part of paper which contains the High Value Question which is designed to test the knowledge on Scientific Concept of the candidates. The questions are analytical in nature where it is necessary for the candidate to apply their scientific logic to reach the solution of the given Scientific Problem.
Note: The revised exam scheme and model Question paper may be seen at CSIR HRDG website https://csirnet.nta.nic.in/
Negative marking for wrong answers, wherever required, shall be applicable as per subject wise scheme of the exam. If in any case, question found to be wrong, benefit of marks will be given to only those candidates who attempt the question. No representation of Answer key after declaration of result will be entertained.
|Course Name||Starting Date||Admission Schedule|
Target Batch NET/JRF Mathematics OFFLINE
*Limited Seats Available
Batch Start: 24th September 2021
|Regular Classroom Program For CSIR NET/JRF MATHS BATCH 2 ( Online only )||
Seminar: 10th July 2021
Batch Start :10th July 2021
Candidates with a good rank in CSIR- UGC NET can pursue PhD programs & add Doctoral and subsequently Postdoctoral degrees to their portfolios. By opting for a PhD degree, you can gain expertise in your field of Mathematics like: Algebra & Number Theory, Analysis, Discrete Mathematics, Geometry & Topology,MathematicalPhysics, Mathematical Biology or any other field.
Assistant Professor or Lecturer post is considered as one of the most prestigious jobs these days.
After receiving the CSIR NET Certificate for lectureship or a NET score, candidates can apply for this post in various government universities.
Apart from this, CSIR NET Qualified candidates are considered on a priority basis in the Private Universities too.
Such candidates can be promoted to higher positions like – ‘Head of Department’, ‘Principle’, ‘Vice-Chancellor’ or ‘Director’.
For UGC NET, UGC JRF, the candidates should have a post-graduation degree (in any of the UGC NET, JRF subjects) with minimum 55% (for General Candidates) or 50% (for ST/SC/PWD/OBC) marks.
For CSIR- UGC NET/JRF, the candidates should have passed M.Sc. / Integrated BS-MS / BS-4 Years / BE/B-Tech / B-Pharma / MBBS with minimum 55% (for General Candidates) or 50% (for ST/SC/PWD/OBC) marks.
The age limit for UGC NET is 30 years for general category and 35 years for ST/SC/PWD/OBC.
The age limit for CSIRUGC NET is 28 years for general category and 33 years for ST/SC/PWD/OBC/ Female Applicants and 31 years for OBC( Non -Creamy Layer).
Question Pattern -
CSIR-UGC NET Exam has only one paper of 3 hours while UGC NET has two papers with the time duration of 3 hours. Each paper of UGC NET has its own specific duration.
The CBSE UGC NET qualified candidates can get a chance to work with NET Coordinating Institutes, whereas CSIR NET qualified candidates can to work with the CSIR Research Laboratories.
It’s possible that even after 6 months you weren't able to crack the exam. Few suggestion given by our faculty are -
It happens to many student in all competitive exams, don’t worry and regroup all your energy and give your 100%. You will succeed in your next attempt.
Focus on the Fundamentals of all the topics, find the weak areas and rework on them.
Get a mentor who can show you the right path and clear all you doubt.
There is no hard and fast rule to crack NET. If your basics of all the topics are clear, you can crack NET in a few months. Few suggestions are-
Go through the syllabus of NET Maths and make sure that you have grasp over all the topics
Get a mentor who can give you right suggestion and direction
Get a mentor who can show you the right path and clear all you doubt.
Revise, revise and revise by solving questions or by going through your hand made notes.
You can get many coaching institutes in Delhi for online and offline classes, and many have just opened their shutters to make money.
Look at the faculty and their reputation
Join a demo session, prior to taking admission
Their should be good sync between the student and mentor
With new technology, you have many options of institutes, that are give online coaching and study material. But since you have planned to spend your precious time, it is of Utmost Importance that you should choose carefully.
Consider an Institute with a proper structure.
What is your objective? Either you want to work on some topics that you find difficult or the whole subject. Or your requirement is completely different that you just need to solve more kind of problems through Mock Tests and discuss their solutions.
Find the mentor who is an expert in this and has a vast experience.
Choose the institute which can fulfill above points.