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What is CSIR NET?



This exam named as CSIR NET is conducted by CSIR (Council of Scientific and Industrial Research) with the objective to determine the eligibility of the candidates of India, which is awarded with Junior Research Fellowships (JRF) /NET (National Eligibility Test) and also to determine eligibility for the appointment of Lecturers (NET) in a number of subjects that fall under the stream of Science & Technology. Exams conducted by CSIR are in the following areas:-

Chemical Sciences

Earth Sciences

Atmospheric Sciences

Ocean Sciences

Planetary Sciences

Life Sciences

Mathematical Sciences

Physical Sciences

Educational Qualification

M.sc or equivalent degree/B.E./B.Tech/MBBS/B.Pharma/BS-4years/Integrated BS-MS with 55% marks for general and OBC-Non Creamy layer candidates and 50% of SC/ST, Persons with disability (PwD) candidates.

Candidates who enrolled for M.Sc or having completed 10+2+3 years of the above qualifying examination, candidates whose result are awaited (RA) are also eligible to apply to the condition that they complete their degree with the requisite percentage of marks within the validity period of two years to avail the fellowship from the effective date of the award.

These types of candidates will have to submit the attestation format (Given on reverse of the application form) duly certified by the Head of the Department/Institute from where the candidate appears or has appeared.

B. SC (Hons) or equivalent degree holders or students enrolled in Integrated MS-PhD program with at least 55 % marks for general and OBC (Non Creamy Layer) candidates; 50% marks for Sc/ST, persons with disability (PwD) are also eligible. The candidates who acquired only a bachelor’s degree will be eligible for the fellowship only after getting enrolled/registered for PhD/ Integrated PhD program within the validity period i.e. 2 years.

The eligibility for lectureship of NET qualified candidates depends on the subject to fulfilling the criteria laid down by UGC. PhD degree holders who have passed Master Degree with minimum 50% marks eligible to apply for Lectureship only.

Examination Centers

The exam will be conducted in more than 27 cities which are spread all over the India. Name of the centres is defined below

Bhopal Bangalore Bhavnagar Bhubaneshwar Chennai Chandigarh Cochin Guntur Delhi
Hyderabad Guwahati Imphal Jamshedpur Jammu Jorhat Kolkata Nagpur Lucknow
Karaikudi Pilani Raipur Srinagar Udaipur Pune Roorkee Thiruvananthapuram Varanasi

Any candidate may opt any of the above describe centers. No request for the change of the center would be granted, however, request in writing may entertain on the merits. If at any center the numbers of appearing candidates are not sufficient, then that particular center may be deleted or any other nearest center will be allotted to the candidate at the discretion of CSIR. No TA/ DA will be allotted to any candidate for attending the exam in any manner.

Age Limit
Exam Name Age Limit
JRF (NET) Maximum 28 years at the time of appearing in the exam (This limit may be relaxed up to 5 years in case of SC/ST/OBC(non Creamy Layer)/ Persons with Disability and female applicants)
LS (NET) No Upper Age Limit
Examination Structure

There are three parts in the CSIR Question Paper named as (A, B & C) as per syllabus & Scheme of Exam

Part A: This is common to all subjects. This part contains questions related to General Aptitude with emphasis on logical reasoning, graphical analysis, numerical ability, quantitative comparison, puzzles, series formation and analytics etc.

Part B: This part contains Multiple Choice Questions (MCQs) covering all the topics in the syllabus

Part C: This is the trickiest part of paper which contains the High Value Question which is designed to test the knowledge on Scientific Concept of the candidates. The questions are analytical in nature where it is necessary for the candidate to apply their scientific logic to reach the solution of the given Scientific Problem.

Note: The revised exam scheme and model Question paper may be seen at CSIR HRDG website https://csirnet.nta.nic.in/

Negative marking for wrong answers, wherever required, shall be applicable as per subject wise scheme of the exam. If in any case, question found to be wrong, benefit of marks will be given to only those candidates who attempt the question. No representation of Answer key after declaration of result will be entertained.

CSIR-NET Mathematics Dec 2024 Open Seminar - CSIR NET/JRF on 10th July 2024
Course Name Class Schedule Fees Enroll Now
CSIR NET Classroom Batch (Offline) Starting 10th July 2024
Read More
Rs. 59,000 Rs. 49,999 /- (Including 18% GST) Enroll Now
CSIR NET Virtual Learning Box Batch Starting 10th July 2024
Read More
Rs. 39,000 Rs. 28,246 /- (Including 18% GST)
(7500 Extra for Study Materials)
Enroll Now
CSIR NET Online Readers Course Starting 10th July 2024
Read More
Rs. 27,000 Rs. 18,999 /- (Including 18% GST)
(7500 Extra for Study Materials)
Enroll Now
CSIR-NET Mathematics Dec 2024 Open Seminar - CSIR NET/JRF on 10th July 2024
Course Name Class Schedule Fees Enroll Now
CSIR NET Classroom (Offline) Starting 10th July 2024
Read More
Rs. 59,000 Rs. 49,999 /- (Including 18% GST) Enroll
CSIR NET Virtual Learning Box Starting 10th July 2024
Read More
Rs. 39,000 Rs. 28,246 /- (Including 18% GST)
(7500 Extra for Study Materials)
CSIR NET Online Readers Course Starting 10th July 2024
Read More
Rs. 27,000 Rs. 18,999 /-
(7500 Extra for Study Materials



Success Stories


How can I clear the CSIR-UGC NET exam in Mathematical sciences?

Few Suggestions given by our faculty are -
  • Look at the NET Syllabus in detail and compare it with your M.Sc Syllabus. If there are areas which are not covered in your M.Sc. Syllabus, then try to cover them. Broadly speaking, try to cover the maximum possible syllabus.
  • Go through the last year question papers and find the weightage of all the topics.
  • Focus on your Strengths, make sure that you have full command over the topic that is your strength.
  • Kindly note that , you don’t have to score 100% to qualify the exam, if you just get 70~ 80% you will be among the leading rank holders.
  • It’s a Multiple Choice Question paper and you should answer all the questions in a limited time, so practice hard to complete the paper in stipulated time.
  • Focus on the basics and fundamentals of all topics.

Which coaching is best for CSIR NET mathematics?

DIPS Academy is considered as the best coaching institute for CSIR NET Mathematics preparations under the mentorship of Award-winning mathematician DUBEY Sir. DIPS Academy is offering online and offline classes for CSIR NET/JRF Mathematics, so student can choose according to their comfort.

What is the fees of CSIR NET math course?

CSIR NET Maths online and offline courses fee varies from Rs 8999 to Rs 65000 at DIPS Academy.

How many DIPS students clear CSIR NET maths?

More than 1000 DIPS Students clear the CSIR NET Maths exam every year.

Which is the best book for preparation of CSIR NET Mathematical Science Exam?

There are multiple books by good authors in each topic, it's suggested to follow JUST One Book For One Topic.Rajendra Dubey Sir has also written a few books on various topics. Link of the books are shared with you here.

Can you suggest some good coaching centres for preparation of CSIR NET Mathematical Science Exam?

Firstly, we never suggest any student to go for coaching, and any hard working student having a good foundation on all topics can easily qualify the CSIR NET Maths exam. DIPS is an academy for Mathematical higher learning which helps to build the foundation of students, so that they are able to become Mathematicians and are able to crack all Mathematical Examinations.

How is your life after qualifying for CSIR-NET in Mathematics?

  1. Candidates with a good rank in CSIR- UGC NET can pursue PhD programs & add Doctoral and subsequently Postdoctoral degrees to their portfolios. By opting for a PhD degree, you can gain expertise in your field of Mathematics like: Algebra & Number Theory, Analysis, Discrete Mathematics, Geometry & Topology,MathematicalPhysics, Mathematical Biology or any other field.

  2. Assistant Professor or Lecturer post is considered as one of the most prestigious jobs these days.

  3. After receiving the CSIR NET Certificate for lectureship or a NET score, candidates can apply for this post in various government universities.

  4. Apart from this, CSIR NET Qualified candidates are considered on a priority basis in the Private Universities too.

  5. Such candidates can be promoted to higher positions like – ‘Head of Department’, ‘Principle’, ‘Vice-Chancellor’ or ‘Director’.

What is the difference among CSIR- UGC NET, CSIR- UGC JRF ,UGC NET and UGC JRF?

UGC NET, UGC JRF is conducted for subjects for streams like Management , Arts etc. But CSIR -UGC NET is conducted only for 5 science streams: Life Sciences, Physical Sciences, Chemical Sciences, Mathematical Sciences and Earth Atmospheric Ocean and Planetary Sciences.
Eligibility -

For UGC NET, UGC JRF, the candidates should have a post-graduation degree (in any of the UGC NET, JRF subjects) with minimum 55% (for General Candidates) or 50% (for ST/SC/PWD/OBC) marks.
For CSIR- UGC NET/JRF, the candidates should have passed M.Sc. / Integrated BS-MS / BS-4 Years / BE/B-Tech / B-Pharma / MBBS with minimum 55% (for General Candidates) or 50% (for ST/SC/PWD/OBC) marks.

The age limit for UGC NET is 30 years for general category and 35 years for ST/SC/PWD/OBC.

The age limit for CSIRUGC NET is 28 years for general category and 33 years for ST/SC/PWD/OBC/ Female Applicants and 31 years for OBC( Non -Creamy Layer).

Question Pattern -
CSIR-UGC NET Exam has only one paper of 3 hours while UGC NET has two papers with the time duration of 3 hours. Each paper of UGC NET has its own specific duration.

The CBSE UGC NET qualified candidates can get a chance to work with NET Coordinating Institutes, whereas CSIR NET qualified candidates can to work with the CSIR Research Laboratories.

Even after dropping 6 months I could not crack the CSIR NET Mathematics. What should I do?

It’s possible that even after 6 months you weren't able to crack the exam. Few suggestion given by our faculty are -

  1. It happens to many student in all competitive exams, don’t worry and regroup all your energy and give your 100%. You will succeed in your next attempt.

  2. Focus on the Fundamentals of all the topics, find the weak areas and rework on them.

  3. Get a mentor who can show you the right path and clear all you doubt.

How do I crack the NET JRF (Maths ) within 2 months?

There is no hard and fast rule to crack NET. If your basics of all the topics are clear, you can crack NET in a few months. Few suggestions are-

  1. Go through the syllabus of NET Maths and make sure that you have grasp over all the topics

  2. Get a mentor who can give you right suggestion and direction

  3. Get a mentor who can show you the right path and clear all you doubt.

  4. Revise, revise and revise by solving questions or by going through your hand made notes.

What is the best coaching institute in Delhi for CSIR NET Mathematical Sciences?

You can get many coaching institutes in Delhi for online and offline classes, and many have just opened their shutters to make money.

  1. Look at the faculty and their reputation

  2. Join a demo session, prior to taking admission

  3. Their should be good sync between the student and mentor

What are some good online coaching classes available for the UGC CSIR NET Mathematical Sciences for people with 9-5 jobs

With new technology, you have many options of institutes, that are give online coaching and study material. But since you have planned to spend your precious time, it is of Utmost Importance that you should choose carefully.

  1. Consider an Institute with a proper structure.

  2. What is your objective? Either you want to work on some topics that you find difficult or the whole subject. Or your requirement is completely different that you just need to solve more kind of problems through Mock Tests and discuss their solutions.

  3. Find the mentor who is an expert in this and has a vast experience.

  4. Choose the institute which can fulfill above points.

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